How many MS20470 AD-4-6 rivets are needed for a 10 x 5 inch plate with a single row of rivets?

To determine the number of MS20470 AD-4-6 rivets needed for a 10 x 5 inch plate in a single row, it's crucial to consider the spacing guidelines typically used in aircraft sheet metal structures.

For rivet placement, there are standard spacing recommendations, usually based on the diameter of the rivets and the type of joint being created. For a standard rivet of this type, spacing is generally around 3 to 4 times the rivet diameter. The AD-4-6 rivet has a nominal diameter of 0.125 inches, which means optimal spacing would range from approximately 0.375 to 0.5 inches between rivets.

Using the average spacing of 0.5 inches, one can calculate the number of rivets for the length of the 10-inch side. Since rivets would also be placed on both ends of the line, you would have:

1. Subtract the rivet diameter from the overall length: 10 inches - 0.125 inches = 9.875 inches.

2. Divide the remaining length by the spacing: 9.875 inches / 0.5 inches = 19.75.

3. Since you cannot have